Data Structures and Algorithms with Object-Oriented Design Patterns in Ruby - The Diigo Meta page

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  • tion can be solved as follows:
    First, we make the simple variable substitution i=n-j:
    

     

  • 
  • 1 more annotations...
  • • The dequeueTail method removes an object from the tail
      of the deque and returns that object.
      First, it verifies that the deque is not empty
      and throws an exception when it is.
      If the deque is not empty,
      dequeueTail saves the last item in the linked list
      in the local variable result.
      Then that item is extracted from the linked list.
      When using the LinkedList class from Chapter ,
      the time required to extract the last item from a list is O(n),
      where is the number of items in the list.
      As a result,
      the running time of DequeueTail is O(n).
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  • Data Structures and Algorithms
    
    
    with Object-Oriented Design Patterns in Ruby
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  harry
  • Axiom 
    The time required to fetch a reference to an object from memory is a constant,
    ,
    and the time required to store a reference to an object in memory is a constant,
    .
  • Axiom 
    The times required to perform elementary arithmetic operations,
    such as addition, subtraction, multiplication, division, and comparison,
    are all constants.
    These times are denoted by
    , , , , and , respectively.
  • 3 more annotations...
  • • Axiom 
      The time required to call a method is a constant, ,
      and the time required to return from a method is a constant, .
    • Axiom 
      The time required to pass an argument to a method
      is the same as the time required
      to store an object reference in memory, .
    • Axiom 
      The time required to create a new object instance of a class
      is a constant, .
      This time does not include any time taken to initialize the object.
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